and 2 2 9. A boy saves 4.65 daily. Find the least numbe 19. W days in which he will be able to save an e 20. SL number of rupees. (Hint: Find L.C.M. of 465 and 100 and 21. G number of days = L.C.M. = 465.) e C. 22. W
Answers
Answered by
2
Answer
Correct option is
B
20
Rs.4.65=465Paise
The exact number of rupees will be a multiple of 100
So, we have to fine the L.C.M. of 465 and 100
100=2×2×5×5
465=3×5×31
L.C.M. of 465 and 100=2×2×3×5×5×31=9300
So, the boy saves 9300 paise.
Hence, least number of days required to save 9300 paise =
465
9300
=20 days
Similar questions