and 4 2. In the figure, ray AB || ray CD. From the and 2 information given in the figure, find the value of x. (HOTS) and Le and I D 100° A B 120° E E D
Answers
Answer:
provision of banana ok Teacher is no true or false in the files I have a great day and potato chips and
Step-by-step explanation:
Corrected Question :
The length and breadth of a room are 18 m and 8 m respectively. Find the cost of covering the floor with tiles at the rate of ₹ 100 per square metre.
To Find : The cost of covering the floor with tiles ?
❍ Finding Area of the floor of Room by the formula is given by :
\begin{gathered}\\\end{gathered}
\boxed{\sf\pink{Area_{(Rectangle)}~=~l~×~b}}
Area
(Rectangle)
= l × b
★
Solution : Here l is the length of Rectangle in metres and b is the Breadth of Rectangle in metres and we have given with length and breadth of a room are 18 m and 8 m respectively.
~~
\underline{\bf{Now~ By~ Substituting~ ~the ~Given~ Values~ :}}
Now By Substituting the Given Values :
\begin{gathered}\\\end{gathered}
:\implies{\sf{Area_{(Floor\: of \:Room)}~=~18~×~8}}:⟹Area
(FloorofRoom)
= 18 × 8
{\underline{\boxed{\frak{\pink{Area_{(Floor \:of \:Room)}~=~144~m^2}}}}}
Area
(FloorofRoom)
= 144 m
2
★
\begin{gathered}\\\end{gathered}
Therefore,
~~~~~~~~~~~ {\sf{Area~of~Room~is~144~m^2}}Area of Room is 144 m
2
~~~~~~~~~ ____________________
\begin{gathered}\\\end{gathered}
❍ Finding Cost of covering the floor of Room with tiles by the formula is given by :
\begin{gathered}\\\end{gathered}
\boxed{\sf\pink{Total~Cost~=~Area \:of \:floor\:×\:Cost\: at \:the \:rate \:of \:m^2}}
Total Cost = Areaoffloor×Costattherateofm
2
Here Area of Room is 144 m² and the cost of rate per square metre is Rs. 100 per square metre.
\begin{gathered}\\\end{gathered}
~
\underline{\bf{Now~By~Susbtitung~the~Given~Values}}
Now By Susbtitung the Given Values
\begin{gathered}\\\end{gathered}
:\implies{\sf{Total~Cost~=~144~×~100}}⟹Total Cost = 144 × 100
{\underline{\boxed{\frak{\pink{Total~Cost~=~Rs.~14400~m^2}}}}}
Total Cost = Rs. 14400 m
2
★
~
Hence,
\therefore\underline{\sf{Total~Cost~of~Room~flooring~with~tiles~is~Rs.~14400}}∴
Total Cost of Room flooring with tiles is Rs. 14400
\begin{gathered}\\\end{gathered}
More Information :
{\rm{Perimeter_{(Triangle)}\:=\:Side A\:+\:Side B\:+\:Side C.}}Perimeter
(Triangle)
=SideA+SideB+SideC.
{\rm{Perimeter_{(Rectangle)}~=~2(Length~+~Breadth).}}Perimeter
(Rectangle)
= 2(Length + Breadth).
{\rm{Perimeter_{(Square)}~=~4~×~Side.}}Perimeter
(Square)
= 4 × Side.
{\rm{Circumference_{(Circle)}~=~2~×~π~×Radius.}}Circumference
(Circle)
= 2 × π ×