Question

and 468
Find the smallest number divisible by 2053 and 967 and leaves a remainder
of 5 and 7 respectively.
Find the HCF and ICM of 144. 180 and 192 by using prime factorization method.​

Answer 1

Step-by-step explanation:

solved it by primefactorisation

Answer 2

Answer:

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your answer is here !

Step-by-step explanation:

  2053 - 5 = 2048 and 967 - 7 = 960  

Prime factorisation of 2048 and 960 are as follows,

  2048 = 2^11 and 960 = 2^6 × 3 × 5  ..

HCF(2048, 960) = 2^6 =64  

Therefore, the largest number which divides 2053 and 967 and leaves  remainder  5 and 7 respectively is 64