Question

And and equal side of an isosceles triangle is 48cm and the area is 108 cm find the area of a triangle

Answer 1

Answer:

Length of base = 48 cm

length of 1 equal side = x cm

Total length of 2 equal sides = 2x cm

Perimeter = side1 + side2 + side3 = 48 cm + x cm + x cm = 48 cm + 2x cm = 108 

 = 48 cm + 2x cm = 108 cm

= 2x cm = 108 cm - 48 cm = 60 cm

= x = 60/2 cm = 30 cm

Therefore, all sides of triangle are 48 cm , 30 cm & 30 cm.

Area of isosceles triangle =  1/2 X base X sq. root of [ (ength of equal side2 - base2 / 4]

= 1/2 X 48 X sq. root of [ 30 X 30 - 48 X 48 / 4]

= 24 X sq. root of [ 900 - 576 ] = 24 X sq. root of [ 324 ]

= 24 X 18 = 432 cm2

Therefore, area of the triangle is 432 cm2

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