Question

α and β are the zeros of the polynomial ax2+bx+c then 1/α²+1/β²​

Answer 1

Since α and β are zeroes.....

➜β+α = -b/a

➜α.β = c/a

To find the value of..... 1/α² + 1/β²

1/α² + 1/β² = (1/α + 1/β)² - 2/βα

= (α+β/αβ)² - 2/αβ

= (-b/a / c/a)² -2/ c/a

= (-b/c)² -2a/c

= -b²/c² - 2a/c

= -b²-2a(c) / c²

= -(b² +2ac) / c²

mark as brainliest...