α and β are zeroes of polynomial
x ^3 −2x+1, then product of zeroes of a polynomial having zeroes 1/α and 1/β is
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Step-by-step explanation:
a+ ß= -paß =q
Vol 84
(1/a + 1/3) = (a + B) /aß = - p/q
1/αβ = 1 / q.
If 1/a, 1/3 are zeros of the quadratic polynomial then the equation is
x2 -(1/a + 1/B)x + 1/aß = 0 then
x2 -(-p/q)x + 1/q=0
qx2 + px + 1 = 0
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