α and β are zeros of polynomial x²-4√3x+3 . Find α and β
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Heya !!!
P(X) = X² - 4✓3X + 3
Here,
A = 1 , B = -4✓3 and C = 3
Discriminant = B²-4AC
=> (-4✓3)² - 4 × 1 × 3
=> 48 - 12
=> 36
Therefore,
X = -B (+-) ✓D / 2A
X = 4✓3 (+-) ✓36 / 2 × 1
X = 4✓3 (+-) 6 / 2 = 2✓3 (-+) 3
Hence,
2✓3 - 3 and 2✓3 + 3 are two zeroes of the given quadratic polynomial.
★ HOPE IT WILL HELP YOU ★
P(X) = X² - 4✓3X + 3
Here,
A = 1 , B = -4✓3 and C = 3
Discriminant = B²-4AC
=> (-4✓3)² - 4 × 1 × 3
=> 48 - 12
=> 36
Therefore,
X = -B (+-) ✓D / 2A
X = 4✓3 (+-) ✓36 / 2 × 1
X = 4✓3 (+-) 6 / 2 = 2✓3 (-+) 3
Hence,
2✓3 - 3 and 2✓3 + 3 are two zeroes of the given quadratic polynomial.
★ HOPE IT WILL HELP YOU ★
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