Question

And,
BD = 160 m, we have
DE = 160 m 2 = 80 m
DE? + CEP = DC, which gives
CE = DCP – DE
160 m
80 m
Dr,
CE = 1002 – 80m=60 m
Fig. 12.14
Therefore, area of A BCD =
m
X160 X 60 m² = 4800 m2
2
EXERCISE 12.2
A park, in the shape of a quadrilateral ABCD, has Z C= 90°, AB = 9 m, BC=12m.
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4cm, CD = 40
CD=5 m and AD = 8 m. How much area does it occupy?
2.
DA=5 cm and AC=5 cm.
Radha made a picture of an aeroplane with coloured paper as
the total area of the paper used.
3.
Redbeanade a picture of an aseroplane with coloured paper as shown in Fig 12.15 pm
5cm​

Answer 1

Answer:

BD - 160 m, we have

DE 160 m 2 80 m

DE + CE-DC, which gives

CE - VDC - DE

160 m

And

D

CE - 100 - 80m=60 m

Fig. 12.14

1

Therefore, area of A BCD --x160 x 60 m² = 4800 m²

2

EXERCISE 12.2

1. A park, in the shape of a quadrilateral ABCD, has 2 C = 90°, AB = 9 m, BC =

CD-5 m and AD = 8 m. How much area does it occupy?

2. Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD =

DA=5 cm and AC=5 cm.

Step-by-step explanation:

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