Question

and drop of Mercury of equal radii and possessing equal charge combine to form a big drop what is the ratio of the capacitance of big and small drop​

Answer 1

let r=radius of small drop

R=radius of big drop

C1/C2=4π€R/4π€r=R/r

R=N^1/3r

C1/C2=N^1/3

Answer 2

Hg=mercury

When We combine the draw small and big then we have the ratio 1:3