Question

And elevator descends into a mine shaft at the rate of 4 meter per minute. What will be its position after 1 hour?
If it begins to descend from 10 metre above the ground what will be its position after 40 minutes from the ground?

Answer 1

Answer:

Distance descended is denoted by a negative integer,

Initial height =+10 m

Final Depth =−350 m

Total distance to be descended by the elevator =(−350)−(+10)=−360 m

Given, the time is taken by the elevator to descend −6 m=1 minute

Thus, time taken by the elevator to descend −360 m=

(−6)

(−360)

------- [from the formula : speed=

time

distance

]

=60 minutes