Question

and equal tots.
4. Find the value of k such that the quadratic equation: x (x - 2k) + 36 = 0, has real and
equal roots.
Also find its roots.​

Answer 1

Answer:

The roots are +6 and -6

Step-by-step explanation:

x²-2kx+36=0

The equation is of the form ax²+bx+c=0

Since the roots are real and equal,

D=b²-4ac=0

a=1,b=-2k,c=36

b²-4ac=0

(-2k)²-4.1.36=0

4k²=144

k²=36

k=±6

The roots are +6 and -6