Question

and hence find nature of its roots.
Find the 13th term of the Arithmatic progression 4, 1, -2, -5,...
5.​

Answer 1

Answer:

a=4 and d=-3 therefore thitheenth term =4+12*-3=-32

Answer 2

AP....4,1,-2,-5...

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d = a2 - a1

d = 1 - 4

d = -3

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a13 = a+12d

a13 = 4 + 12 × (-3)

a13 = 4 - 36

a13 = 32

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