Question

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Answer 1

Answer:

6] d] , 7] b] , 8] b] , 9] a] , 10] d]

Step-by-step explanation:

6] d] 3

       ax^2+bx+c = 0

       3x^2+4x-6 = 0

    so a = 3

7] b] 0        

        ax^2+bx+c = 0

        3x^2+0x-4 = 0

   so b = 0

8] b] (5x-7) + 3(x+4)-2 = 0

  as in ax^2+bx+c = 0

   a should never be 0 , then only it is a quadratic equation .

9] a] 4x^2-8x-5 = 0

       = 4x(x-2) + 5

       = 4x^2-8x-5 = 0

10] d] 2x^2+10x-22 = 0

    = 3x + (x+5)(2x-3) = 7

    = 3x + 2x^2-3x+10x-15 = 7

    = 2x^2+10x-22 =0