Math, asked by Dhruvx, 1 year ago

and i request u to solve this question handwritten. so it will be easier for me to understand!! thanks

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Answered by sumitrabadajena
0

Cot thita tan (90 - thita ) - sec ( 90 - thita ) cosec thita + ( sin2 25+ sin2 65) + root 3 ( tan 5 tan 15 tan 30 tan 75 tan 85 )

= cot thita cot thita - cosec thita cosec thita+ ( sin2 25 + cos2 (90 - 65) + ( tan 60 tan 30 tan 5 tan 85 tan 15 tan 75 )

=cot2 thita - cosec2 thita + sin2 thita + cos2 thita + tan60 cot(90-30) tan 5 cot(90-85) tan 15 cot(90-75)

=1 +1+ tan60 cot 60 tan 5 cot 5 tan 15 cot 15

= 2 + tan 60*1/tan 60  tan5*1/ tan 5 tan 15*1/tan 15

=2+1

=3

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