Question

and it can be opened by a Lever of length 0.25 m by applying a force of 80 Newton what should be the length of liver if a force of 32 newton is enough to open the net​

Answer 1

Answer:

.

Step-by-step explanation:

THE TUNING IS THE SAME IN BOTH THE CASES

 T1=T2

LOAD *LEVER ARM =LOAD * LEVER LENGTH

80 * 0.25* 10^-2 =32 * LEVER LENGTH

LEVER LENGTH = 80*0.25*10^-2 /32

LEVER LENGTH = 0.625= 62.5