А
and
L
is
same
A highly sugid Cubical block .
A of
Small
mass
M and side L is fixed rigidly on to
another
Cubical block B
of the
dimensions and of lower face
completely Lower face of A
completely Lower the upper
face of B. The
lower face B
rigidly held
horiz antal
Sufface. A
Small force
applied
to
perpendicular to one of A after
faces of A. After
the forces is with drown, block .A
executes small
odcillations
the time
period of
given by
|
Answers
Answered by
0
Answer:
Your question is out of my mind
Answered by
1
Answer:
Option is D
Explanation:
Modulus of rigidity η=F/Aθ
Here, A=L ^2
and θ= x/L for small θ
∴ Restoring force =F=−ηAθ
or acceleration, a= F/m= ηL/M equation(1)
∵a∝(−x)
∴ Time period, T=2π root of |x/a|
⟹T=2π root of M/ηL
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