Physics, asked by alimd2508, 2 months ago

А
and
L
is
same
A highly sugid Cubical block .
A of
Small
mass
M and side L is fixed rigidly on to
another
Cubical block B
of the
dimensions and of lower face
completely Lower face of A
completely Lower the upper
face of B. The
lower face B
rigidly held
horiz antal
Sufface. A
Small force
applied
to
perpendicular to one of A after
faces of A. After
the forces is with drown, block .A
executes small
odcillations
the time
period of
given by
|​

Answers

Answered by simranpriya398
0

Answer:

Your question is out of my mind

Answered by elannick89
1

Answer:

Option is D

Explanation:

Modulus of rigidity η=F/Aθ

 

Here, A=L ^2

and θ= x/L   for small θ

 

∴ Restoring force =F=−ηAθ

or acceleration, a= F/m= ηL/M   equation(1)    

​  

∵a∝(−x)

∴ Time period, T=2π root of |x/a|

⟹T=2π root of M/ηL

It Took a lot of time please mark brainliest answer

​  

 

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