Question

and m are intersected by a transversal p show that the quadrilateral formed by the bisector of interior angles is a rectangle​

Answer 1

Step-by-step explanation:

Show that the quadrilateral formed by the bisectors of interior angles is a rectangle. ... Bisectors of interior angles intersect at B and D. ... ABCD is a rectangle.

Answer 2

solution .....

given...

1) let take l and m are intersected by a transversal p

2)the quadrilateral formed by the bisector of interior angles is a rectangle

Two parallel line l and m are intersected by a transversal 'p' show that the quadrilateral formed by bisectors of interior angel is a rectangle. Transversal p intersects l & m at A & C respectively. ... For lines AB and DC with AC as transversal ∠BAC & ∠ACD are alternate angles, and they are equal. So, AB∥DC.

hence ...

But angle LGH+ ANGLE LHG+ Angle GLH=180°

(ANGLE SUM PROPERTY)

90°+angle GLH=180°

(°.° angle LHG + angle LGH =90° )

Angle GLH = 90°

THUS in a parallelogram we have angle GLH =90°

hence , GMHL is a rectangle

i hope it helpfull to you