And object 2cm height placed at a distance of 16 cm from a concave mirror with produces a real image 3 cm height what is the focal length of the mirror and position of image
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Given: O = 2cm, u = 16cm(-ve)I = 3cm(-ve) {Image is real and inverted)-v/u = I / O v = -1(I * u/o) = (-3cm * -16cm/2 cm) = 24 cm (-ve)
To find: focal length, f=? Position off image=?
Solution:Using the relation, 1/f = 1/u + 1/v1/f = 1/-16 + 1/-24= 3 + 2/-48= -5/48
∴f = 48/5 (-ve) = 9.6 cm(-ve)∵ C > u > f Image formed is beyond C
:)
To find: focal length, f=? Position off image=?
Solution:Using the relation, 1/f = 1/u + 1/v1/f = 1/-16 + 1/-24= 3 + 2/-48= -5/48
∴f = 48/5 (-ve) = 9.6 cm(-ve)∵ C > u > f Image formed is beyond C
:)
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