Question

and object moves through 10 m into 2 minutes and next 10 metre in 3 minutes calculate its average speed​

Answer 1

Average speed refers to the total distance covered divided by the total time.

Here, an object moves through 10 m into 2 minutes and next 10 metre in 3 minutes. We'll be calculating average speed in its SI unit, that is m/s (metre per second) . So, we'll first convert minutes into seconds.

Converting time into its standard form :

1 minute consists of 60 seconds. So, in order to find how many seconds does 2 minutes and 3 minutes consist, we'll multiply 60 seconds with 3 and 2.

$\longmapsto$ 1 minute = 60 seconds

$\longmapsto$ 2 minutes = ( 2 × 60 ) seconds

$\longmapsto$ 2 minutes = 120 seconds

Similarly,

$\longmapsto$ 3 minutes = ( 3 × 60 ) seconds

$\longmapsto$ 3 minutes = 180 seconds

Now, finding total time taken by the object ::

$\longrightarrow \sf{ Total \: Time = ( 120 + 180) \: s}$

$\longrightarrow \sf{ Total \: Time = 300 \: s \dots \pmb{\mathfrak{(1)}}}$

Total distance travelled ::

As the object travelled 10 m first and then 10 in next, so

$\longrightarrow$ Total distance = 10 m + 10 m

$\longrightarrow \sf{ Total \: Distance = 20 \: m \dots \pmb{\mathfrak{(2)}}}$

As we know that,

$\bigstar \: \boxed{\sf { Speed_{(avg)} = \dfrac{Total \: Distance}{Total \: Time} }}$

Substituting the value of total distance and total time from $\pmb{\mathfrak{(1)}}$ and $\pmb{\mathfrak{(2)}}$.

$\longrightarrow \sf {Speed_{(avg)} = \dfrac{20 \: m}{300 \: s} }$

$\longrightarrow \sf {Speed_{(avg)} = \dfrac{2 \: m}{30 \: s} }$

$\longrightarrow \sf {Speed_{(avg)} = \dfrac{1 \: m}{15 \: s} }$

$\longrightarrow \boxed{\sf {Speed_{(avg)} = 0.066 \: m/s }}$

Therefore, its average speed is 0.066 m/s.

Answer 2

Answer:

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