And one of the number a, a +2 and a+4 is the muntiple of :
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Hello friends .
( a+2 ) ( a+4 )
= a×a +( 2 +4 ) a+ 2×4
a^ 2 + 6a +8
OR
a , a + 2 , a + 4
a , ( 3 + a ) - 1 , ( 3 + a ) + 1
So Let , a be ___ 3m ( Euclid's )
3m + 1 Division )
3 m + 2 ( Lemma )
If , a is 3 m , Then divisible by 3
If , a is 3 m + 1 , Then , a + 2
3 m + 3 = 3 ( m + 1 )
It is divisible by 3
If a , is 3 m + 1 , Then , a + 4
= 3 m + 6 = 3 ( m + 2 )
Divisible by 3
a , a + 2 , a + 4 is such that at least one of them is divisible by 3 .
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