And only these answer
because tomorrow is my exam
please tell before 2 hrs
Attachments:
Answers
Answered by
2
Here acceleration a=0.1 m/s
Time t=2min= 120 sec
Initial speed u= 0
a) from the first eq of motion v= u+at
=0+0.1*120=12m/s
b) From IInd eq of motion
Distance travelled,
s=ut+1/2 at square
=0*120+1/2* 0.1*120*120
=0.1*60*120
=720m
Time t=2min= 120 sec
Initial speed u= 0
a) from the first eq of motion v= u+at
=0+0.1*120=12m/s
b) From IInd eq of motion
Distance travelled,
s=ut+1/2 at square
=0*120+1/2* 0.1*120*120
=0.1*60*120
=720m
Richard111:
thanx
Similar questions