Question

and q.
7 Find all the zeroes of the following polynomial
when one of its zeroes is given
(i) pſx) = x3 - 8x2 + 19x - 12, having one of its
zeroes as 4.
(ii) px) = x + (3 - 2)x - 3V2 , having one of its
zeroes as 2.
(iii) p(x) = 2 x + x - 7x-6, having one of its
zeroes as 2.
​

Answer 1

Answer:

We are given the following polynomial:

x^3 - 8x^2 + 19x - 12

4 is a zero of given polynomial.

Thus, we can write (x-4) is a factor of the given polynomial.

g(x) = \dfrac{x^3-8x^2+19x-12}{x-4}\\\\g(x) = x^2 - 4x + 3

Factorizing, the obtained polynomial:

Thus, x = 1, 3 and 4 are the zeroes of the given polynomial.

If 2 zeros of a polynomial are -5 and 1. find all the zeros of the polynomial x^4+8x^3+6x^2-40x+25​