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Solve 8(x-3)-(6-2x) = 2(x+2)- 515-x)?​

Answer 1

Answer:

answer : x = 3

explanation : use this basic concepts of algebra to solve the question.

8(x - 3) - (6 - 2x) = 2(x + 2) - 5(5 - x)

or, 8x - 24 - 6 + 2x = 2x + 4 - 5 ×5 + 5x

or, (8x + 2x) - (24 + 6) = (2x + 5x) + 4 - 25

or, 10x - 30 = 7x - 21

or, 10x - 7x = 30 - 21

or, 3x = 9

or, x = 3

hence, value of x = 3

verification :

LHS = 8(x - 3) - (6 - 2x)

= 8(3 - 3) - (6 - 2 × 3)

= 8 × 0 - (6 - 0) = 0

RHS = 2(x + 2) - 5(5 - x)

= 2(3 + 2) - 5(5 - 3)

= 2 (5) - 5(2)

= 10 - 10 = 0

hence, LHS = RHS

so, value of x = 3 is correct.

Answer 2

Correct Question:

Solve:- 8(x - 3) - (6 - 2x) = 2(x + 2) - 515 - x.

Given:

The equation -

• 8(x - 3) - (6 - 2x) = 2(x + 2) - 515 - x

What To Find:

We have to

• First, solve the given equation.
• Next, find the value of x.

Solution:

8(x - 3) - (6 - 2x) = 2(x + 2) - 515 - x

Remove the brackets in LHS,

⇒ 8x - 24 - 6 + 2x = 2(x + 2) - 515 - x

Remove the brackets in RHS,

⇒ 8x - 24 - 6 + 2x = 2x + 4 - 515 - x

Rerrange the like terms in LHS,

⇒ 8x + 2x - 24 - 6 = 2x + 4 - 515 - x

Solve the like terms in LHS,

⇒ 10x - 30 = 2x + 4 - 515 - x

Rearrange the like terms in RHS,

⇒ 10x - 30 = 2x - x + 4 - 515

Solve the like terms in RHS,

⇒ 10x - 30 = x - 511

Take 30 to RHS,

⇒ 10x = x - 511 + 30

Take x to LHS,

⇒ 10x - x = - 511 + 30

Subtract x from 10x,

⇒ 9x = - 511 + 30

Add - 511 and 30,

⇒ 9x = - 481

Take 9 to RHS,

⇒ x = - 481/9

Final Answer:

∴ Thus, the value of x is - 481/9.