Question

and the cases of quaduc polynomial &
erify the relationship between rews and
co-eff of polynomials f(x) =x^2–3x–28



​

Answer 1

Answer:

x²-3x-28

X²-7x+4x-28

x(x-7)+1(x-7)

x=7 or x=-1

let

$\alpha = 7and \beta = - 1$

a=1, b=-3, and c=-28

sum of the zeroes=alpha +beta

=-1+7=6

-b/a=-(-3)/1=3

product of the zeroes=alpha ×beta

7×-1=-7

c/a=-28/1=-28