Question

And the modulus and argument of complex no. 2√3i -2​

Answer 1

Answer:

Correct option is

C

∣z∣=4;amp(z)=

3

2π

∣z∣=2

1+3

=2.2=4

And let α be the argument of the complex number.

Then

tanα=−

3

Now Re(z)<0 and Im(z)>0

Hence,

z=4(

2

−1+

3

i

)

α=π−

3

π

=

3

2π