Question

and the values of K so that the area of the triangle with
vertices [1,-1) {-4, 2k)
and (-k,-5) is 24 sq units​

Answer 1

Answer:

Area of triangle=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

Here x1=1,x2=-4.x3=-k

y1=-1,y2=2k,y3=-5

SOLUTION:......

1/2|1(2k-(-5)+-4(-5-(-1)+-k(-1-2k)|=24

1/2|2k+5+16+k-2k|=24

1/2|k+21|=24

|k+21|=24×2=48

|k+21|=48

|k|=48-21=27

k=27