and this 4th question of maths
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If we solve the polynomial we get
x³+(a+1)x²+x(7+a)+7=x³+2x²+bx+c
from here
a+1=2⇒a=1
7+a=b⇒7+1=b⇒8=b
7=c
∴a+b+c=1+ 8 +7
=16
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