Question

and this one . .............​

Answer 1

Answer:

what is this I can't understand

Answer 2

Answer :

We know that, the nth term of the AP is;

an = a+(n−1)d

a4 = a+(4−1)d

a4 = a+3d

In the same way, we can write,

a8 = a+7d

a6 = a+5d

a10 = a+9d

Given that,

a4+a8 = 24

a+3d+a+7d = 24

2a+10d = 24

a+5d = 12 …………………………… (i)

a6+a10 = 44

a +5d+a+9d = 44

2a+14d = 44

a+7d = 22 ………………………….. (ii)

On subtracting equation (i) from (ii), we get,

2d = 22 − 12

2d = 10

d = 5

From equation (i), we get,

a+5d = 12

a+5(5) = 12

a+25 = 12

a = −13

a2 = a+d = − 13+5 = −8

a3 = a2+d = − 8+5 = −3

Therefore, the first three terms of this A.P. are −13, −8, and −3.