Question

And This one too!! Please

Answer 1

(i)

a^2 + b^2 = 13 , ab = 6

(a + b)^2   =  a^2 + b^2 + 2ab

(a + b)^2   =  13 +2*6

(a + b)^2   =   13 + 12

(a + b)^2   =    25

a + b         =    $\sqrt{25}$

(ii)

(a - b)^2    =  a^2 + b^2 - 2ab

(a - b)^2    =  13 - 2*6

(a - b)^2    =   1

a - b          =   $\sqrt{1}$

a - b          =    1