Math, asked by alpapatel27180, 16 days ago

andard 10 • MATHEMATICS • Board Ion Pap 46. Find the area of the quadrilateral PQRS. Whose vertices, taken in order are P(2,3), 0(3,-2), R(-3,-5) and 5(-4,-2).​

Answers

Answered by gharatkartik241
1

Step-by-step explanation:

Find the area of the quadrilateral PQRS whose vertices in order are P(−5,−3),Q(−4,−6),R(2,−1) and S(1,2).

Area of a quadrilateralPQRS=Area of △PQS+Area of △QSR

We have Area of triangle=21∣x1x2x3y1y2y3111

Let P(−5,−3),Q(−4,−6),R(2,−1)  and S(1,2).

Area of △PQS=21−5−41−3−6

mark me brainlest and follow it

Similar questions