Andrea is three times as old as her sister Anu. Three years ago, she was two years less than four times the age of her sister. Find their present ages.
Answers
SOLUTION:-
Let 'x' and 'y' be the present ages of Andrea and Anu respectively.
Given : Andrea is three times as old as her sister Anu.
x = 3y ----(1)
Three years ago, Andrea was two years less than four times the age of her sister Anu.
Then,
x - 3 = 4(y - 3) - 2
x - 3 = 4y - 12 - 2
x - 3 = 4y - 14
Add 3 to each side.
x = 4y - 11 ----(2)
From (1) and (2),
3y = 4y - 11
Subtract 3y from each side.
0 = y - 11
Add 11 to each side.
11 = y
Substitute 11 for y in (1).
(1)===> x = 3(11)
x=33
So, the present ages of Andrea and Anu are 33 years and 11 years respectively.
Answer:
Sister's age = 11 years
Andrea's age = 33 years
Step-by-step explanation:
Let x and 3x be the age of Andrea's sister and Andrea respectively.
Age of sister = x - 3
Age of Andrea = 3x - 3
Age of Andrea = two years less than four times the age of her sister.
3x - 3 = 4(x - 3) - 2
3x - 3 = 4x - 12 - 2
3x - 3 = 4x - 14
3x - 4x = -14 + 3
-x = -11
x = 11
Sister's age = 11 years
Andrea's age = 3x = 3 x 33 = 33 years