Question

Andrew made 9 baskets out of the 15 shots he took in the first basketball game of the season. In the second game, he made 12 baskets and the percent of baskets he made was the same as the first game. How many shots did Andrew take in the second game?

Answer 1

Answer:

20

Step-by-step explanation:

9/15 = .6 = .6 x 100 = 60%

12/.6 = 20

Answer 2

Andrew took 20 shots in the second game.

Step-by-step explanation:

Andrew made 9 baskets out of the 15 shots he took in the first basketball game of the season.

Percentage of baskets Andrew did in the first game = $\frac{9}{15}\times 100$ = 60%

In the second game, he made 12 baskets.

The percentage of baskets he made was the same as the first game.

Let x be the number of shots in the second game.

$\frac{12}{x}\times 100 = 60%$

=> x = $\frac{12\times 100}{60}$ = 20

Hence, Andrew took 20 shots in the second game.