Math, asked by smshylahaj, 9 months ago

Andy buys K packets of crisps. Laura buys 2 more packets of crisps than Andy. A) write an expression for the total number of packets of crisps . B) there were 14 packets of crisps bought altogether.How many did Andy buy? C) each packets of crisps cost 60p . How much did they each spend?

Answers

Answered by taherbohri10
2

Answer: A) 2K+2, B) 6, C) Andy spends = 360p and  Laura pays = 480p

Step-by-step explanation: Andy buys K packets of crisps

Laura buys two more packets of crisps than Andy = K+2

Therefore,

The total number of packets = K+(K+2)

                           = K+K+2

                           = 2K+2

2K+2 = 14

2K = 14-2

2K = 12

K = 12/2

K = 6

Therefore, Andy had bought 6 Packets

Number of packets Andy bought = 6

Number of Packets Laura bought = 6+2 = 8

Cost of each packet = 60p

Therefore,

Andy pays = 6*60p = 360p

Laura pays = 8*60p = 480p

Answered by CandyBar10
0

Answer:

Step-by-step explanation:

Packets of crips brought by Andy= K

Packets of crips brought by Laura= K+2

a) Total = K+(K+2)

b) Total = 14 packets  

2K + 2 = 14

2K = 14-2

2K= 12

K= 12/2

K=6          Hence Andy brought 6 packets

c) Each packet price = 60p

Amt. Andy paid = 6*60p

                        =  360p

Amt. Laura paid = 6+2

                          =  8

                        =   8*60p

                         = 480p

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