Question

Andy has twice as many marbles as Pandy , and Sandy has half as many has Andy and Pandy put together. If Andy has 75 more marbles than Sandy. How many does each of them have ?

Answer 1

Let Pandy has x no. of marbles.
Thus, no. if marbles with Andy= 2x
No. of marbles with Sandy=( x+2x)/2 = 3x/2
A/q,
2x= 75+3x/2
=> 2x= (150+3x)/2
=> 4x = 150+3x
=> x= 150.

Thus, Pandy has 150 marbles.
Marbles with Andy= 2*150= 300
Marbles with Sandy= (3*150)/2
= 450/2=> 225.

Answer 2

Answer:Let Pandy has x no. of marbles.

Thus, no. if marbles with Andy= 2x

No. of marbles with Sandy=( x+2x)/2 = 3x/2

A/q,

2x= 75+3x/2

=> 2x= (150+3x)/2

=> 4x = 150+3x

=> x= 150.

Thus, Pandy has 150 marbles.

Marbles with Andy= 2*150= 300

Marbles with Sandy= (3*150)/2

= 450/2=> 225.

Read more on Brainly.in - https://brainly.in/question/1359912#readmore

Step-by-step explanation: