Question

Anewer this please
As early as possible​

Answer 1

Let it's one zero be m

Then it's other zero will be 1/m

Product of zeroes=c/a

m * 1/m = 6a/(a^2 + 9)

1 = 6a/(a^2 + 9)

a^2 + 9 = 6a

a^2 - 6a + 9 = 0

a^2 - 3a - 3a + 9 = 0 ( using middle term spilling)

a(a - 3) - 3(a - 3) = 0

(a - 3) (a - 3) = 0

a = 3 or a = 3

So a will be 3