Question

angel between two planes??​

Answer 1

Step-by-step explanation:

let the planes be a1x+b1y+c1z+d1=0

and a2x+b2y+c2z+d2=0

normal vector of the two are a1i+b1j+c1k and a2i+b2j+c2k

use dot product to find the angle between the two and supplementary of that angle will be your answer

imagine two planes their normal meet and make a cyclic quadrilateral

so let the angle between the planes be A

cos(180-A)=(a1a2+b1b2+c1c2)/[|a1i+b1j+c1k| x |a2i+b2j+c2k|]

hope it helps u

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