Question

angel of a triangle are in A. P. if smallest angel is 40degree find the largest angle​

Answer 1

Answer:

Step-by-step explanation:

smallest angle = 40°

let the difference be d

then other angle are 40°+d and 40°+2d

∵sum of all angles of triangle = 180°

⇒40°+(40°+d) +(40°+2d) = 180°

⇒120°+3d=180°

⇒3d=60

⇒d = 20°

so others angles are 40°+20° = 60° and 40°+ 40° = 80°

Answer 2

Answer:

40, 60, 80

Step-by-step explanation:

given angles are in AP

therefore let angles be 40, 40+d and 40+2d

so, 40+40+d+40+2d=180

120+3d=180

3d=60

d=20

so, the angles are 40, 60 and 80