angels a b c d = 3:4:5:6 find all the angles of the trapezium
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for angles ... u hav writtren angels
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Hi ,
a , b , c and d are angles of a
Trapezium ,
a : b : c : d = 3 : 4 : 5 : 6
Let
a = 3x ;
b = 4x ;
c = 5x ;
d = 6x :
We know that ,
Sum of the 4 angles in a quadrilateral
= 360°
3x + 4x + 5x + 6x = 360°
18x = 360
x = 360/18
x = 20
Therefore ,
Required angles are ,
a = 3x = 3 × 20 = 60°
b = 4x = 4 × 20 = 80°
c = 5x = 5 × 20 = 100°
d = 6x = 6 × 20 = 120°
I hope this helps you.
:)
a , b , c and d are angles of a
Trapezium ,
a : b : c : d = 3 : 4 : 5 : 6
Let
a = 3x ;
b = 4x ;
c = 5x ;
d = 6x :
We know that ,
Sum of the 4 angles in a quadrilateral
= 360°
3x + 4x + 5x + 6x = 360°
18x = 360
x = 360/18
x = 20
Therefore ,
Required angles are ,
a = 3x = 3 × 20 = 60°
b = 4x = 4 × 20 = 80°
c = 5x = 5 × 20 = 100°
d = 6x = 6 × 20 = 120°
I hope this helps you.
:)
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