Question

Angie started selling snacks in the nearby school. In one day she spends P270 for rent and P27.50 for each snack item she prepares. Her expenses in a single day can be expressed as the function C(r) = 27.5r + 270, where r is the number of items and C(r) is his daily expenses in pesos. How much are her expenses if she prepares 135 snack items? 150 snack items? ​

Answer 1

Given:

Expense of Angie for rent = P 270

Expense for each snack prepared by Angie = P 27.50

Angie's single day expense is expressed by the function $C(r) = 27.5r + 270$

r = number of items

Cr = daily expenses in pesos

To find:

1. Her expenses when she prepares 135 snack items
2. Her expenses when she prepares 150 snack items

Solution:

• When she prepares 135 snack items

From the given data, the number of days are fixed as one day. For that one day, the cost of rent is also fixed in the given function. The only variable is the number of items Angie prepares in that one particular day.

Now, using the given function, the expenses of Angie when she prepares 135 snack items in one day can be calculated as:

⇒$C(135) = (27.5 (135)) + 270\\C(135) = 3712.5 + 270\\C(135)= 3982.5$

∴ The cost of Angie's expenses in one day, if she prepares 135 snack items is P 3982.50.

• When she prepares 150 snack items

As mentioned above, the number of days is fixed as one day in this condition also. The same calculation done the above case can be used in this case. The change for this case is the number of snack items prepared.

Using the given function, Angie's expenses when she prepares 150 snack items in one day can be calculated as:

⇒$C (150) = (27.5 (150)) + 270\\C (150) = 4125 + 270\\C(150) = 4395$

∴ The cost of Angie's expenses in one day, if she prepares 150 snack items is P 4395.

Hence, found.