ANGLE A=2/3a,ANGLE B=3/5a,ANGLE C=11/15a,SO SOLVE THE VALUE OF a IN ∆ABC.
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2/3 a + 3/5 a + 11/ 15 a = 180
a ( 2/3 + 3/5 +11/15 ) = 180
a ( 10+9+11 / 15 ) =180
a (30/15) = 180
a= 180/2
a= 90
hence value of a is 90
a ( 2/3 + 3/5 +11/15 ) = 180
a ( 10+9+11 / 15 ) =180
a (30/15) = 180
a= 180/2
a= 90
hence value of a is 90
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