Angle A=50°,CD|| BA, angle ECD=60°,the angle ABC
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70o Because, Here, = ∠ACE = ∠BAC = 50o [Alternate angles] = ∠ACB + ∠ACE + ∠DCE = 180o [Linear pair] = ∠ACB = 180o – (50o + 60o) = ∠ACB = 1800 – 110o = ∠ACB = 70°
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