Question

Angle A = 6x+10 angle B = 5x angle c = x+y angle D = 3y-10 find 4 angles

Answer 1

IN A CYCLIC QUADRILATERAL SUM OF OPPOSITE ANGLES IS 180

SO,A+C=180

6x+10+x+Y=180

7x+y=170 ----------------------1

AND

B+D=180

5x+3y-10=180

5x+3y=190 ---------------2

7x+y=170

MULTIPLYING 1 BY 3

21x+3y=510

5x+3y=190

ON SUBTRACTING

16x=320

x=20

BY PUTTING THE VALUE IN 1

y=30

A=130

C=50

B=100

D=80