Question

Angle A=80° BD and CD Are bisector of Angle B and c find angle BDC
​

Answer 1

Answer:

mark as brainliestsanswer follow me

Step-by-step explanation:

a triangle ABC angle A=80 degree, if BD and CD are internal bisectors of angle B and angle C respectively, then the angle BDC is,

In triangle ABC angle A + Angle B +angle C = 180 Deg

Angle B +angle C = 180 Deg- angle A

=180-80=100 deg

In triangle BDC angle DBC + angle DCB + BDC = 180 deg

angle DBC = 1/2 angle B ( angular bisectors)

angle DCB = 1/2 angle C

In triangle BDC 1/2 angle B +1/2 angle C + BDC = 180 deg

In triangle BDC 1/2 (angle B + angle C) + BDC = 180 deg

=1/2(100)+BDC= 180 deg

angle BDC = 180 -50

angle BDC= 130 deg