Question

angle a and angle b are supplementary angles . angle a = (x + 10)° and angle b = (2x-10)° find angle a and angle b.​

Answer 1

Question:-

angle a and angle b are supplementary angles . angle a = (x + 10)° and angle b = (2x-10)° find angle a and angle b.

Answer:-

• angle a = 70°
• angle b = 110°

Solution:-

• Sum of both angles = 180° (supplementary angles)
• angle a = (x + 10)°
• angle b = (2x-10)°

$\large{ \tt : \implies \: \: \: \: {}(x + 10) + (2x - 10) = 180}$

$\large{ \tt : \implies \: \: \: \: {}3x + \cancel 10 - \cancel 10 = 180}$

$\large{ \tt : \implies \: \: \: \: {}3x = 180}$

$\large{ \tt : \implies \: \: \: \: {}x = \frac{180}{3} }$

$\large{ \tt : \implies \: \: \: \: {}x = 60}$

• Value of x is 60°
• angle a = (x + 10)° = 60 + 10 = 70°
• angle b = (2x-10)° = 2(60) - 10 = 120 - 10 = 110°

Answer 2

Answer:

a = 70°

b = 110°

Step-by-step explanation:

As we know that:

Supplementary angles are equal to 180°

so, a + b = 180°

x + 10 + 2x - 10 = 180

3x + 0 = 180

x = 180 ÷ 3

x = 60

Now putting above value of x in a = (x + 10)° and b = (2x - 10)°

a = (60 + 10)°

a = 70°

b = {2(60) - 10}°

b = (120 - 10)°

b = 110°

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