Angle A and angle B form a liner pair , if angle A=5a+16 degree and angle B =a+104 degree .find 'a' and the measure of angle A
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Answered by
1
since angle A and angle B forms a linear pair, then
angle A + angle B=180°,
5a+16° + a+104° =180°
6a+120°=180°,
then
6a=180°-120°,
6a=60°,
then
a=10°,
therefore
angle A=5×10°+16°,
angle A=50°+16°=66°
angle A + angle B=180°,
5a+16° + a+104° =180°
6a+120°=180°,
then
6a=180°-120°,
6a=60°,
then
a=10°,
therefore
angle A=5×10°+16°,
angle A=50°+16°=66°
Answered by
0
given angle A = 5a + 16
and angle B = a + 104
sum of linear angles = 180°
A + B = 180
5a + 16 + a + 104 = 180
6a = 180 - 120
6a = 60
a = 10
so angle A = 5a + 16 = 5× 10 + 16 = 66°
angle B = a + 104 = 10 + 104 = 114°
hence , a = 10 , and the measure of angle A = 66°
and angle B = a + 104
sum of linear angles = 180°
A + B = 180
5a + 16 + a + 104 = 180
6a = 180 - 120
6a = 60
a = 10
so angle A = 5a + 16 = 5× 10 + 16 = 66°
angle B = a + 104 = 10 + 104 = 114°
hence , a = 10 , and the measure of angle A = 66°
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