Question

Angle A = ?
Angle ABO =?
Angle ACB=?​

Answer 1

2angleA=100

angleA=50

angleA+angleB+angleC=180

50+2x+2z=180

25+x+z=90

z=65-x

in tri ocb

100\

+

Answer 2

Answer:

<A=50°

<ABO=25°

<ACB=65°

Step-by-step explanation:

<BOC=100°

<A=<BOC/2=100/2=50°

<OBC=<OCB

<OBC+<OCB+<BOC=180°

<OBC+<OCB=180- <BOC

=180-100=80°

<OBC=80/2=40°

<OCB=80-40=40°

Triangle OBC;

<O=100°

<OBC=<OCB

<OBC+<OCB+<O=180°

<OBC+<OCB=180-100=80°

<OBC=80/2=40°

<OCB=80-40=40°

Triangle ABC;

<A=50°

<B=<C

<A+<B+<C=180°

<B+<C=180-50

=130°

<B=130/2=65°

<C=130-65=65°

<ABO=<B- <OBC

=65-40=25°

<ABO=<ACO

<ACO=25°

<ACB=<ACO+<OCB

=25+40=65°