Question

angle A-B =33° and angle B-C= 18, then
find the angle A,B,C​

Answer 1

question

angle A-B =33° and angle B-C= 18, then

find the angle A,B,C

Answer

given-

A-B=33 and B-C=18

to find=

angle A,B,C=?

solution

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Let A-B=33 (1) equation (given)

and B-C=18 (2). equation (given)

subtract equation 1 and 2

A-B= 33

-C+B=18

A-C=51., equation (3)

as we know

LA+LB+LC=180

51+LC+18+LC+LC=180 (from equation 2and 3)

69+ 3LC=180

3LC=180-69

3LC=111

LC=37

angle c is 37

in equation 2

B-C=18

B=18+37

LB=55

in equation (3)

A-C=51

A=51+37

LA=88

LA=88

LB=55

LC=37

thanks

!!!hope its helpful!!!!!

Answer 2

Given

A-B°= 33°

B-C°= 18

To Find

Angle A,B and ∠C

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

∠A-∠B= 33°-----(1)

∠B-∠C=18°-------(2)

Add equation (1) and (2)

=>∠A-∠B+∠B-∠C= 33°+18°

=>∠A-∠C=51°

∠A=33°+∠B------(3)

from Equation (2)

∠c=-(18° -∠B)-----(4)

Property of triangle

• In a triangle the sum of all Interior angles is equal to 180°.

In ∆ABC

=>∠A+∠B+∠C=180°

From equation (2) and (3) substitute value of ∠A and ∠C

=>33°+∠B-18°+∠B+∠B=180°

=>3∠B+33°-18°=180°

=>3∠B+15=180

=>3∠B=165

=>∠B=165/3

=>∠B=55

Therefore,∠B=55°

From Equation 3 and 4

∠A=33°+∠B

=>∠A=33+55°

=>∠A=88°

=>∠C= -18+∠B

=>∠C= -18+55

=>∠C=37°

Therefore,∠A=88° ; ∠B= 55° & ∠C=37°

Check:

∠A+∠B+∠C=180°

=>88°+55°+37°

=>143°+37°

=>180°