Angle 'a' of a quadrilateral abcd is 26 degree less than angle b. Angle b is twice angle c and angle c is 10 degree more than angle d. What would be the measures of angle a?
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Answer:
angle a = 40
Step-by-step explanation:
sum of all angles of quadrilateral is 360
a + b + c + d = 360
b = a + 26
c = 2b = 2(a+26) = 2a + 52
d = c - 10 = 2a + 52 - 10 = 2a + 42
a + a + 26 + 2a + 52 + 2a + 42 = 360
6a + 120 = 360
6a = 360 - 120
6a = 240
a = 240/6 = 40
a = 40
b = a + 26 = 40 + 26 = 66
c = 2a + 52 = 2(40) + 52 = 80 + 52 = 132
d = 2a + 42 = 2(40) + 42 = 80 + 42 = 122
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