Angle A of an isosceles trapezium is 115° ; find the angles B, C and D.
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opposite angles of isosceles trapezium are supplementary
therefore, angle A + angle C=180°
115°+ angle C= 180°
angle C = 180°-115°
angle C = 65°
and angle B + angle D =180°
let angle B and angle D be x
hence,
angle B + angle D = 180°
x+x=180°
2x=180°
x=180/2
x=90°
therefore, measures of angles B,C and D are 90° , 65° and 90°
hope it helps
and don't forget to mark this as a brainliest ;-)
therefore, angle A + angle C=180°
115°+ angle C= 180°
angle C = 180°-115°
angle C = 65°
and angle B + angle D =180°
let angle B and angle D be x
hence,
angle B + angle D = 180°
x+x=180°
2x=180°
x=180/2
x=90°
therefore, measures of angles B,C and D are 90° , 65° and 90°
hope it helps
and don't forget to mark this as a brainliest ;-)
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