Question

Angle A of Parallelogram ABCD is 12 less than 5 times the measure of the consecutive angle (Angle B). What are the measures of these angles?

Answer 1

Step-by-step explanation:

let A is x and B be 2x-12

A+B= 180

x+2x-12=180

3x-12=180

3x=168

x= 56

then solve B U will get the angle

thank you

Answer 2

The measures of the angles are $28^{o}$ and $152^{o}$.

Step-by-step explanation:

Given:

             ⇒ ∠A and ∠B are the two consecutive angles.

            ⇒ ∠A = 5∠B + 12

Now, we know that sum of two consecutive angles of a parallelogram is $180^{o}$.

So,  

          ⇒ ∠A + ∠B = 180

          ⇒ 5∠B + 12 + ∠B = 180

          ⇒ 6∠B = 168

              ⇒ ∠B =  $28^{o}$

and

        ⇒ ∠A = 5 x  $28^{o}$ + 12

      ⇒ ∠A =  $152^{o}$